54 releases (26 breaking)
new 0.27.0 | Feb 28, 2025 |
---|---|
0.25.1 | Feb 28, 2025 |
0.22.0 | Dec 20, 2024 |
0.21.0 | Nov 14, 2024 |
0.15.2 | Jul 12, 2024 |
#344 in Data structures
1,007 downloads per month
265KB
5.5K
SLoC
matreex
A simple matrix implementation.
Quick Start
First, we need to import matrix!
.
use matreex::matrix;
Addition
let lhs = matrix![[1, 2, 3], [4, 5, 6]];
let rhs = matrix![[2, 2, 2], [2, 2, 2]];
assert_eq!(lhs + rhs, matrix![[3, 4, 5], [6, 7, 8]]);
Subtraction
let lhs = matrix![[1, 2, 3], [4, 5, 6]];
let rhs = matrix![[2, 2, 2], [2, 2, 2]];
assert_eq!(lhs - rhs, matrix![[-1, 0, 1], [2, 3, 4]]);
Multiplication
let lhs = matrix![[1, 2, 3], [4, 5, 6]];
let rhs = matrix![[1, 2], [3, 4], [5, 6]];
assert_eq!(lhs * rhs, matrix![[22, 28], [49, 64]]);
Division
let lhs = matrix![[1.0, 2.0, 3.0], [4.0, 5.0, 6.0]];
let rhs = matrix![[2.0, 2.0, 2.0], [2.0, 2.0, 2.0]];
assert_eq!(lhs / rhs, matrix![[0.5, 1.0, 1.5], [2.0, 2.5, 3.0]]);
Wait, matrix division isn't well-defined, remember? It won't compile. But don't worry, you might just need to perform elementwise division:
let lhs = matrix![[1.0, 2.0, 3.0], [4.0, 5.0, 6.0]];
let rhs = matrix![[2.0, 2.0, 2.0], [2.0, 2.0, 2.0]];
assert_eq!(lhs.elementwise_div(&rhs), Ok(matrix![[0.5, 1.0, 1.5], [2.0, 2.5, 3.0]]));
Or scalar division:
let matrix = matrix![[1.0, 2.0, 3.0], [4.0, 5.0, 6.0]];
assert_eq!(matrix / 2.0, matrix![[0.5, 1.0, 1.5], [2.0, 2.5, 3.0]]);
let matrix = matrix![[1.0, 2.0, 4.0], [8.0, 16.0, 32.0]];
assert_eq!(2.0 / matrix, matrix![[2.0, 1.0, 0.5], [0.25, 0.125, 0.0625]]);
Or maybe the inverse of a matrix?
Nah, we don't have that yet.
FAQs
Why named matreex
?
Hmm ... Who knows? Could be a name conflict.
Dependencies
~1.5MB
~26K SLoC