iso8601-duration

Parse ISO8601 duration format.

https://en.wikipedia.org/wiki/ISO_8601#Durations

Installation

iso8601-duration = "0.2.0"

Usage

use iso8601_duration::Duration;

 assert_eq!(
     "P3Y6M4DT12H30M5S".parse(),
     Ok(Duration::new(3., 6., 4., 12., 30., 5.))
 );
 assert_eq!("P23DT23H".parse::<Duration>().unwrap().num_hours(), Some(575.));
 assert_eq!("P0.5Y".parse::<Duration>().unwrap().num_years(), Some(0.5));
 assert_eq!("P0.5Y0.5M".parse::<Duration>().unwrap().num_months(), Some(6.5));
 assert_eq!("P12W".parse::<Duration>().unwrap().num_days(), Some(84.));

 assert!("PT".parse::<Duration>().is_err());
 assert!("P12WT12H30M5S".parse::<Duration>().is_err());
 assert!("P0.5S0.5M".parse::<Duration>().is_err());
 assert!("P0.5A".parse::<Duration>().is_err());

year and month

Duration can be converted to either std::time::Duration or chrono::Duration by calling to_std or to_chrono.

Both to_std and to_chrono will return None if the duration includes year and month. Because ISO8601 duration format allows the usage of year and month, and these durations are non-standard. Since months can have 28, 29 30, 31 days, and years can have either 365 or 366 days.

To perform a lossless conversion, a starting date must be specified:

// requires `chrono` feature

use iso8601_duration::Duration;
use chrono::DateTime;

let one_month: Duration = "P1M".parse().unwrap();
let date = DateTime::parse_from_rfc3339("2000-02-01T00:00:00Z").unwrap();
assert_eq!(
    one_month.to_chrono_at_datetime(date).num_days(),
    29 // 2000 is a leap year
);

License: MIT